Re: Loads: Weight of steel beams

Richard White

Dear Scott,
I don't want to sound patronising but you have made a common error - 1:87 is
the linear scale, but since you are converting volume you need to cube it,
to give you a multiplier of 658,503.
Try that and see if you don't come out a bit closer.
Richard White

----- Original Message -----
From: Scott Pitzer <scottp459@...>
To: <STMFC@...>
Sent: Saturday, April 24, 2004 7:07 AM
Subject: Re: [STMFC] Re: Loads: Weight of steel beams

Based on Mike Aufderheide's and Fred Swanson's replies, it seems that my
eight 44' beams would be somewhere around 120,000 lbs., so I think I'll go
with that.
But I also tried mixing parts of other replies... to fit my "abilities"
and I know my answer was wrong. Would anyone like to try to figure out why?
Not having a graduated cylinder, I stuck all eight beams halfway into a
measuring cup (that's as far as they'd go) and I divided the resulting
displacement to come up with 3 ml (or 3 cc) displaced by one whole beam.
Since it's already a volume measure, I only have to multiply by 87 to
convert for HO scale, correct? (Not 87x87x87 as when starting with
lengths.) So 3cc scales out to 261cc.
If a cc of steel weighs 8 grams, then the prototype steel beam would weigh
261x8= 2088 grams. If there are about 454 grams in a pound, then the 44'
beam only weighs 4 1/2 pounds!

Scott Pitzer

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